Gujarati
Hindi
3-2.Motion in Plane
normal

A projectile is thrown into space so as to have maximum horizontal range $R$. Taking the  point of projection as origin, the coordinates of the points where the speed of the  particle is minimum are-

A

$(R, R)$

B

$\left( {R,\frac{R}{2}} \right)$

C

$\left( {\frac{R}{2},\frac{R}{4}} \right)$

D

$\left( {R,\frac{R}{4}} \right)$

Solution

$\mathrm{R}_{\mathrm{max}}=\frac{\mathrm{u}^{2}}{\mathrm{g}}$ and when $\mathrm{R}$ is max, then

$H=\frac{u^{2} \sin ^{2} 45^{\circ}}{2 g}=\frac{u^{2}}{4 g}=\frac{R_{\max }}{4}$

Standard 11
Physics

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