A projectile is thrown into space so as to ha | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

$\mathrm{R}_{\mathrm{max}}=\frac{\mathrm{u}^{2}}{\mathrm{g}}$ and when $\mathrm{R}$ is max, then

$H=\frac{u^{2} \sin ^{2} 45^{\circ}}{2 g}=\frac{u^

Vedclass · Accepted Answer

$\left( {\frac{R}{2},\frac{R}{4}} \right)$

Vedclass · Answer

$\mathrm{R}_{\mathrm{max}}=\frac{\mathrm{u}^{2}}{\mathrm{g}}$ and when $\mathrm{R}$ is max, then

$H=\frac{u^{2} \sin ^{2} 45^{\circ}}{2 g}=\frac{u^{2}}{4 g}=\frac{R_{\max }}{4}$

A projectile is thrown into space so as to have maximum horizontal range $R$. Taking the point of projection as origin, the coordinates of the points where the speed of the particle is minimum are-

Similar Questions

A body of mass $m$ is suspended from a string of length $l$. What is minimum horizontal velocity that should be given to the body in its lowest position so that it may complete one full revolution in the vertical plane with the point of suspension as the centre of the circle

A particle is projected from a horizontal plane such that its velocity vector at time $t$ is given by $\vec v = a\hat i + (b - ct)\hat j$ . Its range on the horizontal plane is given by

The vector sum of two forces is perpendicular to their vector differences. In that case, the forces

In projectile motion, the modulus of rate of change of velocity

A small body of mass $m$ slides down from the top of a hemisphere of radius $r$. The surface of block and hemisphere are frictionless. The height at which the body lose contact with the surface of the sphere is